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Timeline for Question on localization technique

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Dec 4, 2012 at 18:37 history edited Fred Rohrer CC BY-SA 3.0
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Dec 4, 2012 at 16:57 vote accept Axy
Dec 4, 2012 at 15:26 comment added Fred Rohrer ... If the result holds in case we have a local base ring then it holds in this situation, and thus the claim will be proven once we prove it for the case of a local base ring.
Dec 4, 2012 at 15:25 comment added Fred Rohrer Dear @Axy, concerning scalar restriction you should take a look at Bourbaki's Algèbre II.1.13. Concerning the proof, I explained that if $M_{\mathfrak{p}}=N_{\mathfrak{p}}$ for every prime ideal $\mathfrak{p}$ in $R_0$, then $M=N$. So, if we want to show that $M=N$, then we have to show that $M_{\mathfrak{p}}=N_{\mathfrak{p}}$ for every prime ideal $\mathfrak{p}$ in $R_0$. To do this, we take such a prime ideal and localise everything at it, obtaining a similar situation as before but this time over a local base ring...
Dec 4, 2012 at 14:56 comment added Axy @Fred Rohrer: Dear Fred, what do you mean by the $B$ modules obtain from $M$ and $N$ by scalar restriction along $h$ are equal ? can you make it more precise? As you said we can conclude that $M_{\mathfrak_{p}}=N_{\mathfrak{p}}$ on $R_0$ and therefore $M=N$ on $R_0$. So, why prooving the problem in the local case makes the proof complete ?
Dec 4, 2012 at 13:35 history answered Fred Rohrer CC BY-SA 3.0