Timeline for Condition for block symmetric real matrix eigenvalues to be real
Current License: CC BY-SA 4.0
5 events
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| Jul 22, 2020 at 20:20 | comment | added | Federico Poloni | A possibly useful step is that after applying a perfect shuffle permutation that matrix takes the form $\Pi^T M_n \Pi = \begin{bmatrix}B+A & -B \\ B & -A-B\end{bmatrix}$, where $A=diag(a_i)=A^T$ and $B = B^T= (b_{ij})$ with zeros on its diagonal. In particular, this matrix is Hamiltonian, which explains the symmetry in the eigenvalues already noticed by @Carlo. | |
| Jul 22, 2020 at 19:19 | history | edited | Rodrigo de Azevedo | CC BY-SA 4.0 |
added 20 characters in body; edited tags
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| Dec 4, 2012 at 16:45 | history | edited | Giulia | CC BY-SA 3.0 |
added 10 characters in body
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| Dec 4, 2012 at 16:14 | answer | added | Carlo Beenakker | timeline score: 1 | |
| Dec 3, 2012 at 17:30 | history | asked | Giulia | CC BY-SA 3.0 |