Timeline for Techniques for showing that a curve is not smoothable

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Dec 3, 2012 at 17:05	comment	added	Charles Staats		Roy: Thanks for the excellent suggestion. Unless I misunderstand, the tangent space dimension will typically be harder to compute than the "expected dimension" (tangent space dimension minus obstruction dimension), since the latter is often accessible via Riemann-Roch. $$ $$ One advantage of this technique is that it is (in principle) capable of working even if we are looking at an irreducible component of the moduli space, some of whose points lie in the closure of the moduli of irreducible curves.
Dec 3, 2012 at 12:12	answer	added	Jason Starr		timeline score: 2
Dec 3, 2012 at 2:42	comment	added	roy smith		the obvious technique is to show the tangent space of the component of moduli has the same dimension as the subset parametrizing reducible curves. E.g. the extreme case is if the reducible curve is "rigid", i.e. does not deform at all.
Dec 3, 2012 at 1:14	history	asked	Charles Staats	CC BY-SA 3.0