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Jan 12, 2010 at 16:50 comment added Pete L. Clark In my answer above, I interepreted "its Lipschitz constant" as "an explicit constant which makes the function Lipschitz", not the least such constant. Off-hand it seems that the one-dimensional constants $L_i$ I gave are sharp but that $L$ I gave need not be. This makes me think that Leonid's answer is better than mine...
Jan 12, 2010 at 10:47 history answered Pete L. Clark CC BY-SA 2.5