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Feb 8, 2016 at 19:48 history edited user9072
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Dec 4, 2012 at 12:27 history edited Felix Goldberg CC BY-SA 3.0
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Dec 4, 2012 at 3:03 comment added fedja Well, just to see that the matrix is invertible requires checking the values of the polynomial with coefficients given by $d$ at all roots of unity, so that part is unavoidable. After that you have just the standard inverse discrete Fourier transform, so there is hardly anything to simplify in that second part. Do you have some particualr restrictions on $d$ that you think might help?
Dec 2, 2012 at 5:47 comment added Yemon Choi Not an answer, but a remark: since the algebra of n-by-n circulant matrices is isomorphic to the algebra of polynomials modulo the ideal generated by $X^n-1$, one might try to use norm estimates for polynomials (something $L^2$ flavoured would be my instinctive starting point)
Dec 2, 2012 at 1:38 history asked Felix Goldberg CC BY-SA 3.0