As Pete already indicated, Mumford's theorem says that for any projective variety $X\subset \mathbb P^n$, its Veronese emberdding $v_d(X)\subset \mathbb P^N$ is cut out by quadrics, for $d\gg0$. So a reasonable question is for the variety with a fixed projective embedding (such as Grassmannians in the Plucker embedding and not in some other random embedding).
For thethis latter more meaningful question, the most classical theoremmany "combinatorial" rational varieties, such as Grassmannians, Schubert varieties (by some classical Italian mathematicianas you pointed out), Petriflag varieties, I think)determinantal varieties, etc., are cut out by quadrics.
For the "non-combinatorial", non-rational varieties, the most classical result is that anyPetri's theorem: a smooth non-hyperelliptic curve, in of genus $g\ge 4$ in its canonical embedding, is cut out by quadrics, with the exceptions of trigonal curves and plane quintics.
There is a vast generatization of this property: $X\subset \mathbb P^n$ satisfies property $N_p$ if the first syzygy of its homogeneous ideal $I_X$ is a direct sum of $\mathcal O(2)$, the second syzygy is a direct sum of $\mathcal O(3)$, etc., the $p$-th syzygy is a direct sum of $\mathcal O(p+1)$. In this language, $X$ is cut out by quadrics is equivalent to the property $N_1$.
A 1984 Green's conjecture is that a smooth nonhyperelliptic curve satisfies $N_p$ for $p=$ its$p=Cliff(X)-1$, where $Cliff(X)$ is the Clifford index minus 1of $X$. I think itThis has been proved for generic curves of any genus by Voisin (in characteristic 0; it is false in positive characteristic).
Another notable case: the ideal of $2\times 2$ minors of a $p\times q$ matrix has property $N_{p+q-3}$.