Timeline for Is this height-transcendence-degree inequality true without AC ?
Current License: CC BY-SA 3.0
8 events
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| Apr 13, 2017 at 12:58 | history | edited | CommunityBot |
replaced http://mathoverflow.net/ with https://mathoverflow.net/
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| Dec 4, 2012 at 14:58 | vote | accept | Ralph | ||
| Dec 4, 2012 at 14:46 | comment | added | Ralph | Quest 2: A somewhat stronger result than $(\ast\ast)$ is given in Prop. 1.1 of the paper [Giral: Krull dimension, transcendence degree and subalgebras of finitely generated algebras. Arch. Math. 36(1981), 305-312] that can be found online here: link.springer.com/article/10.1007%2FBF01223706?LI=true#page-1 | |
| Dec 2, 2012 at 21:24 | comment | added | François Brunault | It's enough to assume the fraction field of $R$ has finite transcendence degree over $k$, since this implies $R$ has finite Krull dimension. | |
| Nov 30, 2012 at 13:38 | answer | added | François Brunault | timeline score: 3 | |
| Nov 29, 2012 at 8:48 | history | edited | Asaf Karagila♦ | CC BY-SA 3.0 |
deleted 15 characters in body
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| Nov 29, 2012 at 0:49 | history | edited | Andrés E. Caicedo |
edited tags
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| Nov 29, 2012 at 0:08 | history | asked | Ralph | CC BY-SA 3.0 |