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Nov 28, 2012 at 1:22 comment added Tom Goodwillie Oh. The point I was missing was that $V\cap H$ must be connected. But can't you simplify your argument further and just find an $H$ through $p$ and $q$ that is transverse to $V$?
Nov 27, 2012 at 17:07 history edited Misha CC BY-SA 3.0
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Nov 27, 2012 at 16:55 history answered Misha CC BY-SA 3.0