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Nov 26, 2012 at 18:47 comment added Joseph Victor To be honest, I didn't mean to write "graded algebra of finite type". I fixed the finite type part.
Nov 26, 2012 at 18:12 comment added Joseph Victor trivial, unless $G$ itself is graded.
Nov 26, 2012 at 18:11 history edited Joseph Victor CC BY-SA 3.0
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Nov 26, 2012 at 9:12 answer added M T timeline score: 1
Nov 26, 2012 at 6:58 comment added Joseph Victor Oops, Why on earth did I write finite type... I must be typing without thinking.
Nov 26, 2012 at 6:56 history edited Joseph Victor CC BY-SA 3.0
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Nov 25, 2012 at 23:45 answer added Ralph timeline score: 4
Nov 25, 2012 at 22:12 comment added Fernando Muro The Steenrod Algebra is not of finite type.
Nov 25, 2012 at 21:30 history asked Joseph Victor CC BY-SA 3.0