Timeline for Absolutely Continuous Invariant Measures for Piecewise Convex Maps
Current License: CC BY-SA 3.0
5 events
| when toggle format | what | by | license | comment | |
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| Dec 3, 2012 at 21:22 | answer | added | Banach | timeline score: 1 | |
| Nov 21, 2012 at 14:41 | comment | added | Tom Kempton | hi fedja, yes f is continuous, I've edited to include this. By 'convex but not strictly convex' I mean that, for $x,y \in [0,1/2]$, f(tx+(1−t)y)≤tf(x)+(1−t)f(y) for each t∈(0,1), but the inequality can't be made strict. The same holds for $x,y$ in [1/2,1]. | |
| Nov 21, 2012 at 14:38 | history | edited | Tom Kempton | CC BY-SA 3.0 |
added 25 characters in body
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| Nov 21, 2012 at 14:24 | comment | added | fedja | What exactly do you mean by (4)? Is $f$ continuous at least? | |
| Nov 21, 2012 at 14:06 | history | asked | Tom Kempton | CC BY-SA 3.0 |