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Feb 23, 2014 at 12:00 comment added Amr @MattNoonan Then square it ?
Dec 21, 2013 at 15:16 history closed Andy Putman
Andrey Rekalo
Stefan Kohl
Daniel Moskovich
Chris Godsil
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Dec 21, 2013 at 1:57 review Close votes
Dec 21, 2013 at 15:16
Jan 11, 2010 at 15:28 vote accept kolistivra
Jan 11, 2010 at 10:00 answer added Pete L. Clark timeline score: 8
Jan 11, 2010 at 6:28 history edited Alon Amit CC BY-SA 2.5
Added +1 to p1p2...pn
Jan 11, 2010 at 6:27 comment added Matt Noonan But what if there is only one composite number!?
Jan 11, 2010 at 6:13 comment added Bjorn Poonen I am reminded of Hendrik Lenstra's proof that there are infinitely many composite numbers: Suppose that there are only finitely many composite numbers. Multiply them together. DON'T add 1!
Jan 11, 2010 at 5:53 comment added Mariano Suárez-Álvarez I agree that finding a counterexample is not the only solution (tertium non datum, and all that...) but I am sure other arguments are consideravly more involved!
Jan 11, 2010 at 5:41 answer added Qiaochu Yuan timeline score: 10
Jan 11, 2010 at 4:36 comment added Qiaochu Yuan Finding a counterexample is the only solution. That's the definition of what it means to disprove a universally quantified statement.
Jan 11, 2010 at 4:07 comment added t3suji I once had this as discrete math homework, the suggested solution was to multiply out and look up a prime number table :)
Jan 11, 2010 at 4:01 comment added Jason DeVito - on hiatus Though the prime factors for n=6 are not entirely obvious without a calculator...
Jan 11, 2010 at 3:40 comment added Mariano Suárez-Álvarez You need only check up to $n=6$...
Jan 11, 2010 at 3:32 history asked kolistivra CC BY-SA 2.5