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Nov 13, 2011 at 20:28 comment added Noam D. Elkies But the exponent of $1-2^{-r} = 1 - 2^{-u}/n$ should be $n-1$, not $n$, right? I checked this for small $n$; it doesn't change the asymptotic oscillation but is needed to account for the discrepancy between the limiting oscillation and the numerical values for finite $n$.
Jan 10, 2010 at 5:18 history edited Reid Barton CC BY-SA 2.5
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Jan 10, 2010 at 0:34 comment added Michael Lugo My computations agree with this.
Jan 10, 2010 at 0:28 history answered Reid Barton CC BY-SA 2.5