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Sep 6, 2010 at 21:09 comment added Joel David Hamkins I show the details of one way to do it in my answer.
Sep 6, 2010 at 19:03 comment added François G. Dorais Could you expand your argument? I see that this works fine in MK (Morse-Kelley Set Theory), but I don't immediately see why it works in NBG. The problem is that NBG does not allow the comprehension of classes by quantification over classes, avoiding that seems non-trivial to me.
Oct 19, 2009 at 10:56 vote accept Philipp Lampe
Oct 19, 2009 at 1:41 comment added Eric Wofsey Sure it is. You can use the Schroder-Bernstein argument to explicitly construct a bijection from A to B given your two injections, for example.
Oct 19, 2009 at 1:21 comment added Philipp Lampe Me either, but is that a proof?
Oct 19, 2009 at 1:17 history answered Eric Wofsey CC BY-SA 2.5