Timeline for First order approximation of the current in ASEP
Current License: CC BY-SA 3.0
5 events
when toggle format | what | by | license | comment | |
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Nov 21, 2012 at 11:12 | comment | added | Daniel | You're right. So I guess one should replace "free" by "as free as it can possibly be". However, here my own intuition ends. | |
Nov 20, 2012 at 18:17 | comment | added | Guillaume | Thank you for your answer and this idea of symmetry. However, I am not sure about the idea of freeness. For example in the case $\rho=1/2$, if the particles were basically free, each particle would move at speed $\gamma$ (averagely), and the currrent would be like $t\gamma/2$ and not $t\gamma/4$. | |
Nov 19, 2012 at 18:46 | history | edited | Daniel | CC BY-SA 3.0 |
added 735 characters in body; added 1 characters in body
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Nov 18, 2012 at 1:36 | comment | added | Guillaume | Yes, but it doesn't really explain why it strictly doesn't depend on rho, and why the transition is at rho = 1/2. | |
Nov 16, 2012 at 18:11 | history | answered | Daniel | CC BY-SA 3.0 |