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Nov 21, 2012 at 11:12 comment added Daniel You're right. So I guess one should replace "free" by "as free as it can possibly be". However, here my own intuition ends.
Nov 20, 2012 at 18:17 comment added Guillaume Thank you for your answer and this idea of symmetry. However, I am not sure about the idea of freeness. For example in the case $\rho=1/2$, if the particles were basically free, each particle would move at speed $\gamma$ (averagely), and the currrent would be like $t\gamma/2$ and not $t\gamma/4$.
Nov 19, 2012 at 18:46 history edited Daniel CC BY-SA 3.0
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Nov 18, 2012 at 1:36 comment added Guillaume Yes, but it doesn't really explain why it strictly doesn't depend on rho, and why the transition is at rho = 1/2.
Nov 16, 2012 at 18:11 history answered Daniel CC BY-SA 3.0