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Dec 7, 2012 at 2:56 vote accept David Cohen
Nov 18, 2012 at 0:18 answer added algori timeline score: 15
Nov 16, 2012 at 2:03 answer added Alexandre Eremenko timeline score: 10
Nov 16, 2012 at 1:58 comment added algori David -- if you are not requiring the embedding to be proper then this should follow from the classification theorem, see e.g. jstor.org/discover/10.2307/… My guess is that starting from this one can construct a proper embedding too.
Nov 16, 2012 at 1:56 history edited David Cohen CC BY-SA 3.0
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Nov 16, 2012 at 1:50 comment added Alexandre Eremenko Similar question was recently discussed here, but I don't now how to find it. Are you asking about topological surface (and topological embedding)? Or a Riemann surface (conformal embedding) or a surface with some metric, or what? I believe that a topological surface, and even a Riemann surface can be so embedded.
Nov 16, 2012 at 1:15 history asked David Cohen CC BY-SA 3.0