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Nov 4, 2013 at 15:03 vote accept Weeson Dorne
Nov 15, 2012 at 8:02 answer added Daniel Spector timeline score: 1
Nov 15, 2012 at 2:06 vote accept Weeson Dorne
Nov 4, 2013 at 15:03
Nov 15, 2012 at 2:06 vote accept Weeson Dorne
Nov 15, 2012 at 2:06
Nov 15, 2012 at 2:05 vote accept Weeson Dorne
Nov 15, 2012 at 2:06
S Nov 15, 2012 at 2:05 vote accept Weeson Dorne
Nov 15, 2012 at 2:05
S Nov 15, 2012 at 2:04 vote accept Weeson Dorne
S Nov 15, 2012 at 2:05
Nov 15, 2012 at 2:04 vote accept Weeson Dorne
S Nov 15, 2012 at 2:04
Nov 14, 2012 at 19:56 answer added Robert Israel timeline score: 1
Nov 14, 2012 at 19:21 comment added Lasse Rempe Since the answer is negative even when the sets $\Omega_j$ are open, it is hard to imagine an assumption where the statement holds and which does not imply that each set contains a ball of some fixed diameter. However, perhaps I am wrong!
Nov 14, 2012 at 18:06 answer added juan timeline score: 1
Nov 14, 2012 at 17:30 history edited Goldstern CC BY-SA 3.0
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S Nov 14, 2012 at 16:34 vote accept Weeson Dorne
Nov 14, 2012 at 16:34
Nov 14, 2012 at 16:32 vote accept Weeson Dorne
S Nov 14, 2012 at 16:34
Nov 14, 2012 at 16:16 history edited Weeson Dorne CC BY-SA 3.0
$\epsilon$ is a constant.
Nov 14, 2012 at 15:32 answer added Lasse Rempe timeline score: 1
Nov 14, 2012 at 15:29 comment added Emil Jeřábek As far as I understand it, the question is not whether the property holds for every such sequence $\Omega_j$ (which is false), but under what additional conditions it holds.
Nov 14, 2012 at 15:16 answer added Gerald Edgar timeline score: 1
Nov 14, 2012 at 15:14 comment added Gerald Edgar I see no reason to close it, since it is not known to non-specialists. More on juan's comment in an answer.
Nov 14, 2012 at 14:10 comment added juan This is well known. If the sets are independents on a probability space there is no such subsequence.
Nov 14, 2012 at 13:59 history asked Weeson Dorne CC BY-SA 3.0