Timeline for smooth morphism on schemes
Current License: CC BY-SA 3.0
6 events
when toggle format | what | by | license | comment | |
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Nov 13, 2012 at 23:20 | answer | added | Qing Liu | timeline score: 2 | |
Nov 13, 2012 at 15:13 | comment | added | Karl Schwede | Matthieu, you are right. I missed the integral implies connected... | |
Nov 13, 2012 at 13:27 | comment | added | Matthieu Romagny |
You write that geometric fibres of $C\to S$ are integral, hence connected ; thus $S'=S$ does the job, doesn't it ?
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Nov 13, 2012 at 13:14 | answer | added | Rob | timeline score: -1 | |
Nov 13, 2012 at 12:30 | comment | added | Karl Schwede | Probably you want $S' \to S$ to be a finite morphism, not just a map of finite type. | |
Nov 13, 2012 at 11:25 | history | asked | Frank | CC BY-SA 3.0 |