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Feb 24, 2013 at 17:51 vote accept Alexander Pruss
Nov 8, 2012 at 17:51 comment added Andreas Blass My recollection (perhaps faulty after all these years) is that some of the early work on nonstandard analysis used "richness" conditions that varied from one paper to another. I believe that some of these were essentially saturation weakened to allow only parameters from the standard model, so that I couldn't use the parameter $n$ in my answer.
Nov 8, 2012 at 16:04 comment added Joel David Hamkins Ramiro, one answer to your question could be that there are advantages to building $\mathbb{R}^\ast$ as an ultrapower by an ultrafilter on $\mathbb{N}$, and these are not supersaturated.
Nov 8, 2012 at 15:18 comment added Ramiro de la Vega Andreas, do you know a context in which having less saturation is better/important/useful? I agree that in principle one could have less saturation, but I´m wondering if you really meant the "sometimes used in NSA".
Nov 8, 2012 at 14:12 history answered Andreas Blass CC BY-SA 3.0