Timeline for Is P(X) a connected set for a set X with a $\sigma$-algebra P(X) and a measure function m on it to [0,$\infty$] when P(X) is equiped with meter d, that for every A,B in P(X), $d(A,B)=m(A \Delta B)$?
Current License: CC BY-SA 3.0
11 events
when toggle format | what | by | license | comment | |
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Nov 13, 2012 at 19:27 | vote | accept | AmirHosein Sadeghimanesh | ||
Nov 13, 2012 at 19:23 | vote | accept | AmirHosein Sadeghimanesh | ||
Nov 13, 2012 at 19:27 | |||||
Nov 13, 2012 at 19:22 | vote | accept | AmirHosein Sadeghimanesh | ||
Nov 13, 2012 at 19:23 | |||||
Nov 13, 2012 at 19:22 | vote | accept | AmirHosein Sadeghimanesh | ||
Nov 13, 2012 at 19:22 | |||||
Nov 12, 2012 at 14:03 | comment | added | Pietro Majer | by the way, the term "atomless" is better than the unclear "non-atomic" (="no atoms at all", or "not atoms only"?), which is also a funny litotes. I'll correct now. | |
Nov 9, 2012 at 13:13 | comment | added | Andreas Blass | As far as I can see, the revised version of the question was already answered affirmatively (before the revision) by Pietro Majer, since Lebesgue measure on a (measurable) subset of the reals is always atomless. | |
Nov 9, 2012 at 13:06 | history | edited | AmirHosein Sadeghimanesh | CC BY-SA 3.0 |
added 589 characters in body
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Nov 7, 2012 at 17:19 | answer | added | Pietro Majer | timeline score: 5 | |
Nov 7, 2012 at 17:06 | comment | added | Davide Giraudo | Not necessarily, for example $X=\Bbb N$,the set of natural numbers, with counting measure. Then \{\emptyset\}$ is open, and so is $\{A\subset \Bbb N,A\neq\emptyset\}=\{A,d(A,\emptyset)>0\}$. | |
Nov 7, 2012 at 17:05 | comment | added | Davide Giraudo | Not necessarily, for example $X=\Bbb N, the set of natural numbers, with counting measure. Then $\{\emptyset\}$ is open, and so is $\{A\subset \Bbb N,A\neq\emptyset\}=\{A,d(A,\emptyset)>0\}$. | |
Nov 7, 2012 at 16:52 | history | asked | AmirHosein Sadeghimanesh | CC BY-SA 3.0 |