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correction; edited body
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S. Carnahan
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Another possible answer, following Qiaochu's comment: The elements $x^2$$x^2$ and $x^3$ (Edit: $x^5$ and $x^3$$x^6$) in $k[x^2, x^3]$ (alternatively, $k[x,y]/(x^3-y^2)$), where $k$ is a nonzero ring.

Another possible answer, following Qiaochu's comment: The elements $x^2$ and $x^3$ in $k[x^2, x^3]$ (alternatively, $k[x,y]/(x^3-y^2)$), where $k$ is a nonzero ring.

Another possible answer, following Qiaochu's comment: The elements $x^2$ and $x^3$ (Edit: $x^5$ and $x^6$) in $k[x^2, x^3]$ (alternatively, $k[x,y]/(x^3-y^2)$), where $k$ is a nonzero ring.

Source Link
S. Carnahan
  • 45.7k
  • 6
  • 114
  • 220

Another possible answer, following Qiaochu's comment: The elements $x^2$ and $x^3$ in $k[x^2, x^3]$ (alternatively, $k[x,y]/(x^3-y^2)$), where $k$ is a nonzero ring.