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Jan 2, 2021 at 16:23 vote accept Anton Geraschenko
Dec 8, 2016 at 3:34 comment added Ben Webster By way, this is very late, but one thing to consider about the characteristic poly definition: this is really saying that you should look at matrices whose minimal polynomial is $x^n$; that's quite different from being nilpotent, as considering the 1 x 1 matrix with a nilpotent entry shows. You were getting confused because you were getting nilpotence from the ring, and nilpotence from the matrix mixed up with each other (which is understandable, since most people think about matrices over fields, and so only have to think about the latter).
Jan 8, 2010 at 18:05 answer added Mariano Suárez-Álvarez timeline score: 16
Jan 8, 2010 at 17:56 answer added Ben Webster timeline score: 12
Jan 8, 2010 at 17:41 history asked Anton Geraschenko CC BY-SA 2.5