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Nov 3, 2012 at 14:04 history edited Aaron Meyerowitz CC BY-SA 3.0
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Nov 3, 2012 at 12:18 history edited Aaron Meyerowitz CC BY-SA 3.0
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Nov 2, 2012 at 7:45 history edited Aaron Meyerowitz CC BY-SA 3.0
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Nov 2, 2012 at 7:45 comment added Gabriel Nivasch Hi Aaron, I agree that if you delay large $u$ and $d$ for as long as possible, then every long run must end "late". But how do you know that every long run must start "early"? Can't you have a long run that starts "late" and ends "late"?
Nov 2, 2012 at 5:13 history edited Aaron Meyerowitz CC BY-SA 3.0
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Nov 2, 2012 at 5:00 history answered Aaron Meyerowitz CC BY-SA 3.0