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Nov 2, 2012 at 17:37 vote accept Sergei Akbarov
Nov 2, 2012 at 7:26 answer added Buschi Sergio timeline score: 5
Nov 1, 2012 at 23:15 comment added David Roberts @Sergei, using the Yoneda lemma it is, because that tells you the functor $X\mapsto Hom(-,X)$ is fully faithful.
Nov 1, 2012 at 22:53 answer added David Roberts timeline score: 8
Nov 1, 2012 at 20:20 comment added Sergei Akbarov Sergio, I don't understand this trick. Is it possible, for example, to prove the diagram of associativity (the pentagon) in this way?
Nov 1, 2012 at 20:03 comment added Buschi Sergio Is easy (elements check) that $Set$ is cartesian (i.e. for finite products) monoidal, then for a general cartesian category you apply the (general) representable $(X, -)$ to the axioms diagrams (and use the result in $Set$), then the commutativity of each diagrams follow from Yoneda Lemma (need only the faithful part).
Nov 1, 2012 at 20:00 comment added Sergei Akbarov Eric, thank you, that's interesting. So this means that the accurate proof exists... It would be nice to look at it...
Nov 1, 2012 at 19:57 answer added Wouter Stekelenburg timeline score: 2
Nov 1, 2012 at 19:41 comment added Eric Peterson I don't know a reference, but I do know this has a name: ncatlab.org/nlab/show/cartesian+monoidal+category .
Nov 1, 2012 at 19:13 history asked Sergei Akbarov CC BY-SA 3.0