Timeline for finding highest weight of dual of a representation of a semisimple lie algebra
Current License: CC BY-SA 3.0
3 events
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| Nov 1, 2012 at 13:59 | comment | added | Sasha |
The reason is that $w_0(\lambda)$ is an antidominant weight of $V$, hence the lowest weight, and the highest weight of $V^*$ is minus the lowest weight of $V$.
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| Nov 1, 2012 at 12:42 | comment | added | Rekha Biswal | @Sasha could you please explain how -w(lamda) will be the highest weight? | |
| Nov 1, 2012 at 10:27 | history | answered | Sasha | CC BY-SA 3.0 |