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Nov 2, 2012 at 19:08 vote accept Andrey
Nov 2, 2012 at 19:08 vote accept Andrey
Nov 2, 2012 at 19:08
Nov 2, 2012 at 2:27 answer added fedja timeline score: 1
Nov 1, 2012 at 8:14 comment added Andrey Dear Fedja, thank you for this suggestion. I am delighted it is not hard, but could you possibly show how to do this? that you cannot beat 1/(4x^2) everywhere on any (0, a)?
Nov 1, 2012 at 3:51 comment added fedja Sorry for an idiotic question: I misread "concave" as "convex". In what sense is the growth you want "the fastest"? It is not hard to show that you cannot beat $1/(4x^2)$ everywhere on any interval $(0,a)$ but you can go a bit above it at places at the cost of going below it at some other places...
Oct 30, 2012 at 12:34 comment added fedja Do you need $g$ to stay bounded near $0$?
Oct 30, 2012 at 12:12 history asked Andrey CC BY-SA 3.0