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S Mar 24, 2022 at 12:34 history suggested The Amplitwist CC BY-SA 4.0
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S Mar 24, 2022 at 12:34
Oct 25, 2012 at 13:59 answer added Alain Valette timeline score: 1
Oct 25, 2012 at 7:35 comment added Alain Valette @Zhaoting: Thanks a lot for the clarification. I think however that you should write $K^n_G(X)$ rather than $K^G_n(X)$, because it is K-theory, i.e. a theory contravariant in $X$.
Oct 25, 2012 at 4:41 history edited Zhaoting Wei CC BY-SA 3.0
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Oct 25, 2012 at 4:34 history edited Zhaoting Wei CC BY-SA 3.0
I defined KG(X) to be the K-theory of the cross product algebra.
Oct 25, 2012 at 3:34 comment added Zhaoting Wei @Alain: (Continued) The index map I am looking for is the same as that in Penington-Plymen paper. I apologize for the confusing I've made and I have made some modifications in the question body to define equivariant K-theory more clearly. Nevertheless it is really appreciated that you pointed out the problem.
Oct 25, 2012 at 3:29 comment added Zhaoting Wei @Alain: Thank you for your comments! Sure I should be more clear about what I want. The second point you made may be because of the non-standard terminology I used. In fact for any Lie group $G$ I define $K^G_0(X)=K(C_r^*(G; C_0(X)))$ where $C_r^*(G; C_0(X))$ is the reduced cross product $C^*$-algebra. Hence the $K_*(C^*_r(G))$ is exactly $K^G_*(pt)$ in my question. As for $R(U)$, since $U$ is compact, $R(U)=K_0(C^*_r(U))$. We also notice that $C^*_r(U)$ is strong Morita equivalent to $C^*_r(G; C_0(G/U))$, hence $R(U)=K^G_0(G/U)$ in this context. The index map I am looking for is the same as
Oct 24, 2012 at 23:05 comment added Alain Valette First, I think that you should be more specific about the properties you expect of an index map. Second, I checked the Penington-Plymen paper and there is no mention of the index map you indicate; their index map goes from the representation ring $R(U)$ to the K-theory $K_*(C^*_r(G))$ of the reduced $C^*$-algebra of $G$.
Oct 24, 2012 at 20:24 history edited Zhaoting Wei CC BY-SA 3.0
In paragraph 3 I drop the assumtion that dim X is even.
Oct 24, 2012 at 17:32 history asked Zhaoting Wei CC BY-SA 3.0