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S Aug 25, 2013 at 13:26 history suggested Michael Albanese
Added the kahler-manifolds tag.
Aug 25, 2013 at 12:57 review Suggested edits
S Aug 25, 2013 at 13:26
Jul 5, 2013 at 13:51 comment added Ben McKay The holonomy doesn't have to be the whole of $SU(n)$, because flat complex Euclidean space has holonomy $\{1\}$ as does any flat complex torus or a product of complex Euclidean space with a flat complex torus. On the other hand, the holonomy could be $SU(n)$.
Jul 5, 2013 at 12:00 answer added Misha Verbitsky timeline score: 2
Oct 25, 2012 at 17:27 comment added Mina does anyone have an idea ?
Oct 24, 2012 at 15:33 history asked Mina CC BY-SA 3.0