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Oct 24, 2012 at 9:47 comment added GH from MO @km: Thank you. In the noncommutative case it is not so clear how to make this approach work as one has higher dimensional representations in the spectrum.
Oct 24, 2012 at 6:43 vote accept user25235
Oct 24, 2012 at 6:43 vote accept user25235
Oct 24, 2012 at 6:43
Oct 24, 2012 at 6:41 comment added user25235 I accept this answer since this is close to what I was looking for. It seems reasonable to expect that your proof extends to the general case (without applying the reduction given by Terence Tao) : given a neighbourhood $U$ of the identity, all what we need is a function $f$ with real, nonnegative fourier transform, with nonzero mean, and which vanishes outside $U$. I don't know if this is always possible.
Oct 23, 2012 at 19:45 history answered GH from MO CC BY-SA 3.0