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Oct 20, 2012 at 19:11 comment added Brian Street Thank you for your answer, which I will have to think about more! The Weierstrass approximation theorem I meant (perhaps Stone-Weierstrass) was that a closed subalgebra of the continuous functions on a compact Hausdorff space, which contains a nonzero constant function, and which separates points is the entire algebra of continuous functions. This can be used in my first comment to show that if all the integrals are actually 0, then a must be 0. That's why I was calling the special case in the comment a quantitative Weierstrass approximation theorem; here take a(x)dx to be a measure,instead
Oct 20, 2012 at 19:04 comment added Alexandre Eremenko Sorry, I did not notice that Fedja posted his answer while I was writing my own:-)
Oct 20, 2012 at 18:59 history answered Alexandre Eremenko CC BY-SA 3.0