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Jan 11, 2010 at 1:30 vote accept CommunityBot moved from User.Id=577 by developer User.Id=69903
Jan 7, 2010 at 4:35 answer added Ian timeline score: 4
Jan 7, 2010 at 4:34 answer added S. Carnahan timeline score: 2
Jan 7, 2010 at 4:06 comment added Qiaochu Yuan Yes, what I gave is a faithful representation of that G.
Jan 7, 2010 at 4:04 history edited user577 CC BY-SA 2.5
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Jan 7, 2010 at 3:49 comment added Mariano Suárez-Álvarez My $G$ was the semi direct product of $\mathbb Z_p\times\mathbb Z_p$ by $\mathbb Z_p$, with the latter's generator acting on the former by the matrix $\left(\begin{array}{cc}1&1\\\\0&1\end{array}\right)$.
Jan 7, 2010 at 3:48 comment added Qiaochu Yuan Also, maybe you should be more explicit about which theorems you want to see the subtleties of.
Jan 7, 2010 at 3:45 answer added Pete L. Clark timeline score: 12
Jan 7, 2010 at 3:44 history edited user577 CC BY-SA 2.5
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Jan 7, 2010 at 3:44 answer added Mariano Suárez-Álvarez timeline score: 6
Jan 7, 2010 at 3:41 comment added Qiaochu Yuan Whoops. Replace "the identity matrix" with "a permutation matrix of order p."
Jan 7, 2010 at 3:39 comment added Qiaochu Yuan If Mariano's G is the G that I'm thinking of, it has the following explicit description: it's the group of p x p matrices generated by the identity matrix, the diagonal matrix with all entries zeta_p, and the diagonal matrix (1, zeta_p, zeta_p^2, ...).
Jan 7, 2010 at 3:26 history edited user577 CC BY-SA 2.5
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Jan 7, 2010 at 3:18 comment added user577 Very good point.
Jan 7, 2010 at 3:13 answer added Qiaochu Yuan timeline score: 2
Jan 7, 2010 at 2:57 comment added Mariano Suárez-Álvarez You may want to be more stringent about what you want, lest you get silly examples like $G\times\mathbb Z_p^{m-3}\times\mathbb Z_r$ with $G$ a non abelian group of order $p^3$ (which you can get as $(\mathbb Z_p\times\mathbb Z_p)\rtimes\mathbb Z_p)$.
Jan 7, 2010 at 2:49 history asked user577 CC BY-SA 2.5