Timeline for Equality of rational maps
Current License: CC BY-SA 3.0
7 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Oct 15, 2012 at 12:04 | vote | accept | gio | ||
| Oct 14, 2012 at 21:59 | comment | added | gio | Pior, I'm sorry, you're right. However, I also mean equality of schemes... | |
| Oct 14, 2012 at 21:30 | comment | added | Qfwfq | @gio: Piotr Achinger answered your question. In his example the equality of the closures does hold (not just for generic points but for every point $x\in X$). Or am I missing somethig? | |
| Oct 14, 2012 at 21:26 | history | edited | Piotr Achinger | CC BY-SA 3.0 |
added 392 characters in body
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| Oct 14, 2012 at 21:23 | comment | added | Piotr Achinger | In my example we have $f^{-1}(f(x)) = g^{-1}(g(x)) = x$ since $f$ and $g$ are both bijective... | |
| Oct 14, 2012 at 20:47 | comment | added | gio | Read carefully my question. I am not required $\overline{f^{-1}(f(x))}\simeq \overline{g^{-1}(g(x))}$ but $\overline{f^{-1}(f(x))}= \overline{g^{-1}(g(x))}$. | |
| Oct 14, 2012 at 20:13 | history | answered | Piotr Achinger | CC BY-SA 3.0 |