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Jan 7, 2010 at 16:23 history edited Kevin Walker CC BY-SA 2.5
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Jan 7, 2010 at 16:18 comment added Kevin Walker Oops -- you're right. That's a silly thing for me to get wrong. I don't immediately see a way to fix my argument above to work in the general case. Maybe by understanding the tangent spaces of Q_1 and Q_2 in more detail one can cook up a perturbation which gets rid of the irreducibles while not changing the reducibles very much? Or maybe there's a simpler, better argument which identifies the homology classes of Q_1 and Q_2 inside H_*(H)?
Jan 7, 2010 at 6:32 comment added Sam Lewallen Thanks, this looks really good! But I don't think being a QHS is enough to guarantee that the reducibles and irreducibles are separated? Sometimes the irreducibles limit to the reducibles (this is discussed in the paper of Boyer and Nicas). That was the case where I really couldn't see what to do... do you have any ideas there? Thanks again!
Jan 7, 2010 at 6:30 history edited Kevin Walker CC BY-SA 2.5
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Jan 6, 2010 at 20:41 history answered Kevin Walker CC BY-SA 2.5