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Jan 6, 2010 at 22:14 history edited Ilya Nikokoshev CC BY-SA 2.5
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Jan 6, 2010 at 21:22 comment added TJCM Yes, just sa Oliver has said, the point is that the Weil divisor is not necessarily a Cartier divisor; and because we are not only considering algebraically varieties, so we cannot even have a good expectation of the normal locus on X.
Jan 6, 2010 at 21:17 comment added Olivier Benoist No, you can't unless Y is a Cartier divisor. in this case X'=X... which is not very interesting !
Jan 6, 2010 at 21:08 comment added Ilya Nikokoshev I'm not good in commutative algebra, but you can reduce to $A$ being a formal ring $k[[x_1, x_2]]$ and $I = (f)$, where $f$ is homogenious and then everything should follow.
Jan 6, 2010 at 20:46 comment added TJCM It can be resated algebraically as follows: A is Noetherian ring, I is a height one ideal, prove that $Proj (\sum_{n>=0} I^n/I^{n+1})$ --> $Spec A/I$ is a finite morphism.
Jan 6, 2010 at 20:34 history answered Ilya Nikokoshev CC BY-SA 2.5