Timeline for Constructing equivalent algebraic expressions for matrix equations
Current License: CC BY-SA 3.0
4 events
when toggle format | what | by | license | comment | |
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Oct 14, 2012 at 7:59 | answer | added | Federico Poloni | timeline score: 1 | |
Oct 14, 2012 at 7:42 | answer | added | Dima Pasechnik | timeline score: 1 | |
Oct 14, 2012 at 0:31 | comment | added | R.P. | There exists a fixed matrix $S$ such that $SAS^{-1}$ is in Jordan normal form. The same is then true for $B_k = SA_kS^{-1}$. So now consider $x^T A_k^{-1} A x = x^T S^{-1} S A_k^{-1} S^{-1} S A x = x^T S^{-1} (S A_k S^{-1})^{-1} S A x = x^T S^{-1} B_k^{-1} S A x$. And $B_k$ is easy to invert. | |
Oct 13, 2012 at 23:38 | history | asked | mks | CC BY-SA 3.0 |