Timeline for Interpolating a sum of binomial coefficients using a sin function
Current License: CC BY-SA 3.0
12 events
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Sep 5, 2013 at 16:08 | history | edited | Pietro Majer | CC BY-SA 3.0 |
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Oct 16, 2012 at 10:38 | comment | added | Stefano Capparelli | Thanks a lot. I really enjoyed your solution. Grazie mille. | |
Oct 16, 2012 at 10:28 | vote | accept | Stefano Capparelli | ||
Oct 16, 2012 at 10:27 | vote | accept | Stefano Capparelli | ||
Oct 16, 2012 at 10:28 | |||||
Oct 12, 2012 at 15:34 | history | edited | Pietro Majer | CC BY-SA 3.0 |
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Oct 12, 2012 at 13:57 | history | edited | Pietro Majer | CC BY-SA 3.0 |
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Oct 12, 2012 at 13:56 | comment | added | Pietro Majer | Yes, sorry, I was in a big hurry and I was taken by some sudden silly doubt. Checking now the details, there were no problem at all, so I roll back to the first version. The identities for the sums are easily proven by induction, and contain a partial product of the infinite product for $\sin(\pi x)/\pi x$. | |
Oct 12, 2012 at 13:47 | history | edited | Pietro Majer | CC BY-SA 3.0 |
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Oct 11, 2012 at 17:34 | comment | added | Matt Young | The sums are polynomials in $x$ so if they agree on the integers then they are equal everywhere. I personally don't see how Maple is computing the sums, but that's another story. | |
Oct 11, 2012 at 15:34 | history | edited | Pietro Majer | CC BY-SA 3.0 |
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Oct 11, 2012 at 15:17 | comment | added | Pietro Majer | mmmh, wait, actually evaluating the sums I assumed x to be an integer! so I'm not sure of the result. | |
Oct 11, 2012 at 14:32 | history | answered | Pietro Majer | CC BY-SA 3.0 |