Timeline for ordered exponential of unbounded operators
Current License: CC BY-SA 3.0
10 events
| when toggle format | what | by | license | comment | |
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| Jul 10, 2017 at 21:21 | vote | accept | André Henriques | ||
| Oct 12, 2012 at 17:14 | comment | added | András Bátkai | Is this what you were looking for or something else? Should I give more details? | |
| Oct 12, 2012 at 15:55 | comment | added | André Henriques | I mistakenly thought that "resolvent" means the same thing as "inverse". | |
| Oct 11, 2012 at 23:11 | comment | added | András Bátkai | @André Henriques: What do you mean then by the statement you do not want to assume boundedness of resolvents? By selfadjointness, you have planty of resolvent points... | |
| Oct 10, 2012 at 20:15 | history | edited | András Bátkai | CC BY-SA 3.0 |
added 292 characters in body
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| Oct 10, 2012 at 20:00 | comment | added | András Bátkai | This is usually satisfied if you have a large common domain ant the maps $t\mapsto A_t x$ are continuous. | |
| Oct 10, 2012 at 19:59 | comment | added | András Bátkai | What about $(1+A_t)^{-1}$? | |
| Oct 10, 2012 at 19:48 | comment | added | André Henriques | I don't want to assume that the resolvents $A_t^{-1}$ are bounded. How should I interpret "strong resolvent continuity" then? | |
| Oct 10, 2012 at 19:39 | history | edited | András Bátkai | CC BY-SA 3.0 |
added 111 characters in body
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| Oct 10, 2012 at 19:32 | history | answered | András Bátkai | CC BY-SA 3.0 |