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Oct 9, 2012 at 23:43 comment added Will Sawin @Adam: I mean that the elements of the class group are literally certain equivalence classes of certain sets of elements of $K$. @Dror: The sets have the same cardinality, so yes, there is.
Oct 9, 2012 at 21:16 comment added Dror Speiser Also, does this mean there is a bijection defined over $\overline{\mathbb{Q}}$?
Oct 9, 2012 at 20:40 comment added Adam Harris @Will:What do you mean by the class group of the endomorphism ring is defined over $K$?
Oct 9, 2012 at 20:23 history answered Will Sawin CC BY-SA 3.0