Timeline for Involution of the Fermat quartic
Current License: CC BY-SA 3.0
8 events
when toggle format | what | by | license | comment | |
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Apr 13, 2017 at 12:58 | history | edited | CommunityBot |
replaced http://mathoverflow.net/ with https://mathoverflow.net/
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May 10, 2014 at 16:09 | vote | accept | Puzzled | ||
Oct 10, 2012 at 16:46 | comment | added | rita | I had tought of this possibility. If I have time I can try to work out a description. Or maybe Francesco will do it... | |
Oct 10, 2012 at 12:29 | comment | added | Puzzled | You are right. The fibration of mathoverflow.net/questions/87633/… is not exactly the one I had in mind, sorry. It is just because I was considering a different fibration on $\mathbb{P}^{1}$, namely the one given by $$ C_{[\mu,\lambda]} = \left\{\begin{array}{l} \lambda (x^{2}-y^{2}) = \mu (z^{2}-t^{2})\\ \lambda (x^{2}+y^{2}) = \mu (z^{2}+t^{2}) \end{array} \right. $$ In this way $X/i$ is a fibration over $\mathbb{P}^{1}$ with $\mathbb{P}^{1}$ as general fiber. | |
Oct 10, 2012 at 8:39 | vote | accept | Puzzled | ||
Oct 10, 2012 at 8:39 | |||||
Oct 10, 2012 at 0:05 | answer | added | Francesco Polizzi | timeline score: 4 | |
Oct 9, 2012 at 20:23 | comment | added | rita | It seems to me that the fibers of the fibration described in mathoverflow.net/questions/87633/… are permuted by $i$, so the quotient surface has an elliptic fibration. | |
Oct 9, 2012 at 17:35 | history | asked | Puzzled | CC BY-SA 3.0 |