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Oct 18, 2012 at 9:25 answer added user26857 timeline score: 1
Oct 8, 2012 at 4:30 history edited Knot CC BY-SA 3.0
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Oct 8, 2012 at 4:29 comment added Knot Yep, thank you all very much for pointing it out. I mean the minimal set of generator.
Oct 8, 2012 at 2:06 answer added Youngsu timeline score: 3
Oct 6, 2012 at 13:43 comment added Karl Schwede I looked up Matsumura page 8 so I think I see what you are asking, you should try googling Graded Nakayama's Lemma. Everything you want is true if you assume that $R$ is $\mathbb{N}$-graded with $R_0$ a field. In particular the same argument goes through from the local case (page 9 of Matsumura).
Oct 6, 2012 at 13:02 comment added Karl Schwede There's definitely more than one choice of generators (since $\langle x,y\rangle = \langle x, y, x+y, x^2, \dots \rangle$. Do you mean a minimal choice of generators?
Oct 6, 2012 at 6:29 history edited Knot CC BY-SA 3.0
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Oct 6, 2012 at 2:47 history asked Knot CC BY-SA 3.0