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Aug 1, 2015 at 19:06 comment added LSpice @grp, what is the definition of semisimplicity that is distinct from geometric semisimplicity? (For those who learned the Jordan decomposition from Borel, they are the same by definition.) Is it that the minimal polynomial is irreducible over $k$?
Oct 3, 2012 at 21:57 vote accept Miguel
Oct 1, 2012 at 11:23 comment added grp The example in #3 (which readily adapts to any imperfect field $k$ using the $k$-linear multiplication by $a^{1/p}$ on $V = k(a^{1/p})$) isn't an entirely satisfactory counterexample because it is semisimple over $k$ (though not "geometrically semisimple"; i.e., not diagonalizable over $\overline{k}$). The Wikipedia entry has now been updated to give an example over any imperfect field $k$ in which the operator isn't a sum of two commuting $k$-linear operators that are respectively semisimple (just over $k$!) and nilpotent.
Sep 29, 2012 at 15:58 comment added Anton Klyachko We should demand that $R$ and $M$ commute.
Sep 29, 2012 at 15:17 history edited Laurent Berger CC BY-SA 3.0
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Sep 29, 2012 at 14:27 history answered Laurent Berger CC BY-SA 3.0