Timeline for Example of continuous function that is analytic on the interior but cannot be analytically continued?
Current License: CC BY-SA 2.5
8 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Jan 6, 2010 at 12:41 | comment | added | Anweshi | I also ask about Hanche-Olsen's objection. | |
| Jan 5, 2010 at 19:38 | vote | accept | Johan | ||
| Jan 5, 2010 at 19:38 | comment | added | Johan | Yeah, that seems to work completely. | |
| Jan 5, 2010 at 19:37 | comment | added | Harald Hanche-Olsen | How do you know that the singularities in the second sum don't cancel each other out? | |
| Jan 5, 2010 at 19:27 | comment | added | Anweshi | Your clarification(both here and in my deleted answer) had been most helpful. Thanks. | |
| Jan 5, 2010 at 19:23 | comment | added | David E Speyer | Because its derivative is not bounded near $1$. | |
| Jan 5, 2010 at 19:20 | comment | added | Anweshi | $f(1) = \zeta(2)$. Why are you saying $f$ is not analytic near $1$? | |
| Jan 5, 2010 at 19:10 | history | answered | David E Speyer | CC BY-SA 2.5 |