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Jul 13, 2017 at 11:32 history edited Joseph O'Rourke CC BY-SA 3.0
Image link broken; now fixed.
Sep 28, 2012 at 15:36 comment added Joseph O'Rourke Thanks everyone---I stand corrected! I will leave my "answer" intact as an instructional error. :-)
Sep 28, 2012 at 15:06 comment added Douglas Zare This is a nice picture, but I think there is a discontinuity in the set of ellipses you can inscribe in a tetrahedron when you degenerate to a rectangle. By the way, a square would work as well.
Sep 28, 2012 at 15:03 comment added Gerhard Paseman Turn it into a (dis-?)proof by embedding an ellipse into a cross-section of the tetrahedron. I think this is a beautifully misleading picture, because it suggests that a tetrahedral cross section can be almost as big as two of the faces, which I believe is never the case for tetrahedra of positive volume with faces of roughly equal area. Gerhard "Almost Like Sixty-Five Equals Sixty-Four" Paseman, 2012.09.28
Sep 28, 2012 at 14:33 comment added Matt Pusey Thanks. I agree that that ellipse looks like it won't fit in a triangle, but I don't agree that it fits inside the tetrahedron. If you try to make a thin tetrahedron like that then a typical cross-section through it will be a diamond which your ellipse wouldn't fit into. If you have Mathematica, the code at pastebin.com/UCAYTPpc shows the sort of tetrahedron I think your talking about and lets you look at cross-sections through it.
Sep 28, 2012 at 13:15 history answered Joseph O'Rourke CC BY-SA 3.0