Timeline for Is the Hasse principle a birational invariant?
Current License: CC BY-SA 3.0
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| Sep 28, 2012 at 9:31 | comment | added | Daniel Loughran | I think for the OP's benefit I should also clarify that for Lang-Nishimura you also need properness. Indeed, given a smooth variety $X$ with a single rational point $x$, the variety $Y=X \setminus x$ is birational to $X$ yet has no rational points. | |
| Sep 28, 2012 at 8:42 | vote | accept | IMeasy | ||
| Sep 27, 2012 at 22:49 | history | edited | R.P. | CC BY-SA 3.0 |
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| Sep 27, 2012 at 21:01 | history | edited | R.P. | CC BY-SA 3.0 |
added 188 characters in body
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| Sep 27, 2012 at 20:53 | history | answered | R.P. | CC BY-SA 3.0 |