Skip to main content

Timeline for Categorical duals in Banach spaces

Current License: CC BY-SA 2.5

8 events
when toggle format what by license comment
Jan 5, 2010 at 18:35 vote accept Reid Barton
Jan 5, 2010 at 18:35 vote accept Reid Barton
Jan 5, 2010 at 18:35
Jan 5, 2010 at 18:30 comment added Reid Barton (Just to spell out exactly how this is related to my original question: Asking for a dual for an object $X$ of a closed symmetric monoidal category is the same as asking for an object $X^*$ and an identification $\mathbf{Hom}(X, {-}) = X^* \otimes {-}$. In particular (using closedness again) $\mathbf{Hom}(X, {-})$ must commute with colimits. In my case $X = (\mathbb{R}^2)_1 = \mathbb{R} \amalg \mathbb{R}$, and so $\mathbf{Hom}(X, V) = V \times V$.
Jan 5, 2010 at 18:15 comment added Reid Barton Here is a concrete counterexample for someone to sanity check. It seems that "the set of extreme points of the unit ball" is an isomorphism invariant of a Banach space, and that it preserves coproducts and products, at least the ones used in forming $(R^{\amalg n})^{\times 2}$ and $(R^{\times 2})^{\amalg n}$. It then sends these spaces to sets of cardinality $(2n)^2$ and $4n$, respectively, which are distinct for $n \ge 2$. This shows that $V \mapsto V \times V$ doesn't commute with coproducts.
Jan 5, 2010 at 18:02 comment added Yemon Choi I think so; see the updated entry.
Jan 5, 2010 at 18:02 history edited Yemon Choi CC BY-SA 2.5
response to comment/query
Jan 5, 2010 at 17:46 comment added Reid Barton And the injective and projective tensor products are non-isometric in this case for general V, right?
Jan 5, 2010 at 17:25 history answered Yemon Choi CC BY-SA 2.5