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Jan 25, 2018 at 0:46 comment added lemiller Sorry to be late to the party, but do the answers change if one replaces X by a smooth rigid analytic space?
Sep 27, 2012 at 3:13 answer added Sándor Kovács timeline score: 4
Sep 27, 2012 at 2:07 comment added LMN Great, thanks! If you reply below, I'll be happy to accept your response as an answer.
Sep 27, 2012 at 1:41 history edited LMN
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Sep 27, 2012 at 1:40 comment added Pavel Safronov Sorry, I didn't understand your question at first. Forms in $j_*\Omega^k_U$ are definitely not $C^\infty$ on $X$, since they are not even defined at $D$. Let me try to be more precise. The kernel of $\Omega^k_X(*D)\rightarrow j_*\Omega^k_U$ consists of meromorphic forms on $X$ which vanish on $U$. Since they are zero on an open set, they are zero on the whole $X$.
Sep 27, 2012 at 1:17 comment added LMN Why do you know that $j_*\Omega_U^k$ is the sheaf of $C^\infty$ differential $k$-forms on $X$ that are holomorphic on $U$?
Sep 27, 2012 at 1:11 comment added Pavel Safronov $j_*\Omega^k_U$ is the sheaf of differential forms which are holomorphic on $U$. You have an inclusion $\Omega^k_X(*D)\subset j_*\Omega^k_U$ of forms meromorphic along $D$. Furthermore, $\Omega^k_X(log D)\subset \Omega^k_X(*D)$ as forms having a first-order pole along $D$.
Sep 27, 2012 at 0:59 history asked LMN CC BY-SA 3.0