###Motivation (added)###
A finite $n$-set is uniquely described (up to isomorphism) by a single population number $n$.
A finite $n$-set with $k$ predicates is uniquely described (up to isomorphism) by $2^k$ population numbers $n_i$, corresponding to the $2^k$ combinations of predicates, $\sum_{i=1}^{2^k} n_i = n$
A finite $n$-set with 1 binary relation (a graph $G$) can be uniquely described (up to isomorphism) by $k$ population numbers $n_i$, corresponding to its $k$ $Aut(G)$-orbits, provided these are appropriately described, $\sum_{i=1}^{k} n_i = n$.
I want to clarify what an appropriate description of the orbits might be and whether there is something like a canonical description of the orbits.
###Definition 1###
###Question 21 (postponed)###
###Definition 2 (correctedthird revision)###
###Comment######Claim###
Distinguishing properties allow not only to distinguish between (equivalence classes of) vertices of a single graph but also to distinguish different graphs: the isomorphism class ofGiven a finite graph is fixed by$G$ and a distinguishing family of properties plusw.r.t. $G$ then the numbers of vertices for each distinguishing propertypopulation function $\phi_v(x)$$f: \lbrace \phi_v(x)\rbrace_{[v] \in G/_\sim} \rightarrow \mathbb{N}$ with $f(\phi_v(x)) = |[v]|$ determines the graph up to isomorphism.
###Definition 2a (my claim, maybe wrong?added)###
A distinguishing family of properties is minimal if its overall number of bound variables is minimal.
(Comment: Minimal distinguishing properties might serve as a canonical form of a graph.)
###Question 3 (editedsecond revision)###
Does it seem feasible to computeCan a distinguishing family of properties be computed from - let's say - the adjacency matrix in linear time? For some small and many highly symmetric graphsOr is this problem provably as hard as graph isomorphism?
Addendum: As pointed out in the second answer (Mariano's) it can be done by handis straight forward to begin with a complete description of the graph (one existential formula, but what about biggerstating that there are exactly $n$ different vertices and more asymmetric graphstheir relations) and make successively each single variable free. In the resulting $|G|$ formulas one then has to find the orbits (= equivalent formulas) which is probably as hard as graph isomorphism.
###Question 3a (added)###
Can a minimal distinguishing family of properties be computed from the adjacency matrix in linear time? Or is this problem provably as hard as graph isomorphism?
- Let a d-neighbour of x be a vertex d edges away from x.
- Let $\phi_d^n$ stand for x has exactly n d-neighbours.
- Let $C_l^n$ be the graph consisting of n cycles of lenght $l, l \geq 2$, $C_2^1 = K_2$.
- Let $P_l$ be the path graph of length $l$.
More examples may follow###(3)###
Consider the path graphs $P_l$ with $\lceil \frac{l}{2} \rceil$ conjugacy classes of vertices. Let $\psi_d$ stand for x has a d-neighbour with degree 1. Then
$\lbrace \phi_1^1 \rbrace\ \cup\ \lbrace \phi_1^2 \wedge \psi_k \rbrace_{k = 1,..,\lceil \frac{l}{2} \rceil - 1}$
is a distinguishing family of properties (not necessarily minimal).