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Sep 25, 2012 at 7:18 history edited Brendan McKay CC BY-SA 3.0
add numbers
Sep 25, 2012 at 5:19 vote accept Ben Golub
Sep 27, 2012 at 4:38
Sep 25, 2012 at 5:13 comment added Gerhard Paseman Oh, and I am guessing the next clique overlaps the previous one in one edge and two vertices. Gerhard "Ask Me About System Design" Paseman, 2012.09.24
Sep 25, 2012 at 5:01 comment added Gerhard Paseman It looks like Ben is happy with your answer, and indeed I am not suprised at the result. However, I suspect there are about n values to be determined (hiding in the O(n^2)), and those n values may require knowing a lot about the graphs on say log n or even sqrt(n) vertices. If I understand Terry's response correctly, his intuition says filling in the missing values will be easier than graph enumeration. Does your intuition tell you something similar to this? Gerhard "We're The Less Than 1%" Paseman, 2012.09.24
Sep 25, 2012 at 4:45 vote accept Ben Golub
Sep 25, 2012 at 4:50
Sep 25, 2012 at 3:26 history answered Brendan McKay CC BY-SA 3.0