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Timeline for Künneth formula for cohomology

Current License: CC BY-SA 3.0

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Sep 23, 2012 at 5:45 comment added Axel Aha, I see what you mean! Thank you!
Sep 22, 2012 at 12:55 comment added Peter May I see what may have been confusing you. As I said (p. 136 original version, 134 of the second edition), you can start with cochain complexes $Y$ and $Y'$ that don't necessarily arise by dualizing chain complexes, and then the Kunneth theorem does apply directly. The finite type question arises from the dualization.
Sep 22, 2012 at 7:42 history answered Axel CC BY-SA 3.0