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Sep 20, 2012 at 14:41 comment added user6976 I included the proof in my answer.
Sep 20, 2012 at 14:28 comment added randl I think so too, but cannot find nor develop a proof.
Sep 20, 2012 at 14:22 history edited user6976 CC BY-SA 3.0
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Sep 20, 2012 at 14:11 comment added user6976 For nilpotent groups $|G':H'|$ should be finite, I think.
Sep 20, 2012 at 13:51 comment added randl If I am not mistaken, for an infinite nilpotent group $G$ the derived group $G^\prime$ must have infinite index. So the general statement in your third sentence does not apply. How do things look if $G$ is nilpotent?
Sep 20, 2012 at 13:47 vote accept randl
Sep 20, 2012 at 13:43 history edited user6976 CC BY-SA 3.0
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Sep 20, 2012 at 13:08 history answered user6976 CC BY-SA 3.0