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Given a special case of WVG (Weighted Voting Game) of $a$ 1s and $b$ 2s and a quota q, $ [q:1,1,1,1..1,2,2,..2] $. I need help with calculating the Shapley value of a player with a weight of $2$ and a player with a weight of $1$ as a function of $a$,$b$ and $q$.

I know how to calculate the Shapely value in general, but I would like to get a simple closed form for the result. I tried to think about what happens if there are only players with weights of $1$ (simple scenario $ a=2k-1,b=0,q=k $ I think you will agree that $ \phi_{1}(v)=\frac{1}{a}=\frac{1}{2k-1} $. the simple calculation is $ \binom{2k-2}{k-1}(k-1)!(k-1)!=\frac{1}{2k-1}=\frac{1}{a} $ which is $ \frac{1}{2k-1} $. The calculation for a player of weight 1 (when there are 1s and 2s) would be a sum of choosing i players of weight 1 and $ \frac{q-i}{2} $ players of weight 2. similar calculation for a player of weight 2.

I tagged binomial coefficients because I thought they could be useful for counting the occurrences.

Thanks in advance, Mati

also posted here: http://math.stackexchange.com/posts/199080https://math.stackexchange.com/posts/199080

Thanks in advance, Mati

Given a special case of WVG (Weighted Voting Game) of $a$ 1s and $b$ 2s and a quota q, $ [q:1,1,1,1..1,2,2,..2] $. I need help with calculating the Shapley value of a player with a weight of $2$ and a player with a weight of $1$ as a function of $a$,$b$ and $q$.

I know how to calculate the Shapely value in general, but I would like to get a simple closed form for the result. I tried to think about what happens if there are only players with weights of $1$ (simple scenario $ a=2k-1,b=0,q=k $ I think you will agree that $ \phi_{1}(v)=\frac{1}{a}=\frac{1}{2k-1} $. the simple calculation is $ \binom{2k-2}{k-1}(k-1)!(k-1)!=\frac{1}{2k-1}=\frac{1}{a} $ which is $ \frac{1}{2k-1} $. The calculation for a player of weight 1 (when there are 1s and 2s) would be a sum of choosing i players of weight 1 and $ \frac{q-i}{2} $ players of weight 2. similar calculation for a player of weight 2.

I tagged binomial coefficients because I thought they could be useful for counting the occurrences.

Thanks in advance, Mati

also posted here: http://math.stackexchange.com/posts/199080

Thanks in advance, Mati

Given a special case of WVG (Weighted Voting Game) of $a$ 1s and $b$ 2s and a quota q, $ [q:1,1,1,1..1,2,2,..2] $. I need help with calculating the Shapley value of a player with a weight of $2$ and a player with a weight of $1$ as a function of $a$,$b$ and $q$.

I know how to calculate the Shapely value in general, but I would like to get a simple closed form for the result. I tried to think about what happens if there are only players with weights of $1$ (simple scenario $ a=2k-1,b=0,q=k $ I think you will agree that $ \phi_{1}(v)=\frac{1}{a}=\frac{1}{2k-1} $. the simple calculation is $ \binom{2k-2}{k-1}(k-1)!(k-1)!=\frac{1}{2k-1}=\frac{1}{a} $ which is $ \frac{1}{2k-1} $. The calculation for a player of weight 1 (when there are 1s and 2s) would be a sum of choosing i players of weight 1 and $ \frac{q-i}{2} $ players of weight 2. similar calculation for a player of weight 2.

I tagged binomial coefficients because I thought they could be useful for counting the occurrences.

Thanks in advance, Mati

also posted here: https://math.stackexchange.com/posts/199080

Thanks in advance, Mati

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Mati
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Dear all, GivenGiven a special case of WVG WVG(Weighted Voting Game) of a$a$ 1s and b$b$ 2s and a quota q, [q:1,1,1,1..1,2,2,..2] $ [q:1,1,1,1..1,2,2,..2] $. I I need help with calculating the shapley valueShapley value of a player with a weight of 2$2$ and a player with a weight of 1$1$ as a function of a$a$,b$b$ and q$q$.

I know how to calculate the Shapely value in general, but I would like to get a simple closed form for the result. I tried to think about what happens if there are only players with weights of $1$ (simple scenario $ a=2k-1,b=0,q=k $ I think you will agree that $ \phi_{1}(v)=\frac{1}{a}=\frac{1}{2k-1} $. the simple calculation is $ \binom{2k-2}{k-1}(k-1)!(k-1)!=\frac{1}{2k-1}=\frac{1}{a} $ which is $ \frac{1}{2k-1} $. The calculation for a player of weight 1 (when there are 1s and 2s) would be a sum of choosing i players of weight 1 and $ \frac{q-i}{2} $ players of weight 2. similar calculation for a player of weight 2.

I tagged binomial coefficients because I thought they could be useful for counting the occurrences.

Thanks in advance, Mati

also posted here: http://math.stackexchange.com/posts/199080

Thanks in advance, Mati

Dear all, Given a special case of WVG of a 1s and b 2s and a quota q, [q:1,1,1,1..1,2,2,..2]. I need help with calculating the shapley value of a player with a weight of 2 and a player with a weight of 1 as a function of a,b and q.

also posted here: http://math.stackexchange.com/posts/199080

Thanks in advance, Mati

Given a special case of WVG (Weighted Voting Game) of $a$ 1s and $b$ 2s and a quota q, $ [q:1,1,1,1..1,2,2,..2] $. I need help with calculating the Shapley value of a player with a weight of $2$ and a player with a weight of $1$ as a function of $a$,$b$ and $q$.

I know how to calculate the Shapely value in general, but I would like to get a simple closed form for the result. I tried to think about what happens if there are only players with weights of $1$ (simple scenario $ a=2k-1,b=0,q=k $ I think you will agree that $ \phi_{1}(v)=\frac{1}{a}=\frac{1}{2k-1} $. the simple calculation is $ \binom{2k-2}{k-1}(k-1)!(k-1)!=\frac{1}{2k-1}=\frac{1}{a} $ which is $ \frac{1}{2k-1} $. The calculation for a player of weight 1 (when there are 1s and 2s) would be a sum of choosing i players of weight 1 and $ \frac{q-i}{2} $ players of weight 2. similar calculation for a player of weight 2.

I tagged binomial coefficients because I thought they could be useful for counting the occurrences.

Thanks in advance, Mati

also posted here: http://math.stackexchange.com/posts/199080

Thanks in advance, Mati

added 66 characters in body
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Mati
  • 101
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Dear all, Given a special case of WVG of a 1s and b 2s and a quota q, [q:1,1,1,1..1,2,2,..2]. I need help with calculating the shapley value of a player with a weight of 2 and a player with a weight of 1 as a function of a,b and q. Thanks

also posted here: http://math.stackexchange.com/posts/199080

Thanks in advance, Mati

Dear all, Given a special case of WVG of a 1s and b 2s and a quota q, [q:1,1,1,1..1,2,2,..2]. I need help with calculating the shapley value of a player with a weight of 2 and a player with a weight of 1 as a function of a,b and q. Thanks in advance, Mati

Dear all, Given a special case of WVG of a 1s and b 2s and a quota q, [q:1,1,1,1..1,2,2,..2]. I need help with calculating the shapley value of a player with a weight of 2 and a player with a weight of 1 as a function of a,b and q.

also posted here: http://math.stackexchange.com/posts/199080

Thanks in advance, Mati

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Mati
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